For what value of k, 2 + 3 = 7 4 + = 14 has unique solution.
Answers
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Step-by-step explanation:
Consider the given equations.
4x+ky+8=0 ……. (1)
2x+3y+7=0 …… (2)
The general equations,
a
1
x+b
1
y+c
1
=0
a
2
x+b
2
y+c
2
=0
Therefore,
a
1
=4,b
1
=k,c
1
=8
a
2
=2,b
2
=3,c
2
=7
Since, the condition of unique solution is
a
2
a
1
=
b
2
b
1
Therefore,
2
4
=
3
k
3
k
=2
k
=6
Hence, k is any real number except 6.
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