for what value of k, - 2 is a zero of the polynomial 3x ^2 +4x+2k
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Answered by
4
Here is your answer....
place that value of x = -2 in the given equation....
3(-2)^2 + 4(-2) + 2k = 0
3×4 - 8 + 2k = 0
12 - 8 + 2k = 0
2k = -4
k = -2
hope this will help you....
if it is helpful then plzz mark it as brainliest...
Answered by
2
3x^2+4x+2k=0
= 3×(-2)^2 + 4×(-2)+2k=0
= 3×4-8+2k=0
= 12-8+2k=0
= 4+2k=0
=2k = -4
=k= -2
= 3×(-2)^2 + 4×(-2)+2k=0
= 3×4-8+2k=0
= 12-8+2k=0
= 4+2k=0
=2k = -4
=k= -2
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