Question

For what value of k 2 k + 1, 3 k + 3 and 5 k - 1 form an arithmetic progression

Answer 1

We know, in arithmetic sequence,

2 × middle term = sum of left terms




Therefore,

= > 2 × ( 3k + 3 ) = ( 5k - 1 ) + ( 2k + 1 )


= > 6k + 6 = 5k - 1 + 2k + 1


= > 6k + 6 = 7k


= > 6 = 7k - 6k


= > 6 = k





Hence, the value of k is 6
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