Question

for what value of k, 2k+7,k+5 and 3k+5 are consequetive terms of an A.P.

Answer 1

d=d  
k+5-(2k+7)=3k+5-(k+5)
k+5-2k-7=3k+5-k-5
-k-2=2k-0
​3k=-2
K=-2/3