For what value of k:2k,k+10 and 3k+2 are in A.P?
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2k,k+10,3k+2
now,
d=a2-a=a3-a2
so,
a2-a=a3-a2
k+10-2k=3k+2-k-10
-k+10=2k-8
10+8=2k+k
18=3k
18/3=k
k=6
the value of k is 6
hope this answer will help you.
now,
d=a2-a=a3-a2
so,
a2-a=a3-a2
k+10-2k=3k+2-k-10
-k+10=2k-8
10+8=2k+k
18=3k
18/3=k
k=6
the value of k is 6
hope this answer will help you.
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0
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