For what value of k; 2k,k+2k and 3k+2are in AP
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i hope this will help u
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Step-by-step explanation
We know that to find common difference=a2-a1 or a3-a2
So
k+2k-2k=k
And 3k+2-(k+2k)=3k+2-k-2k=2
And common difference will always be equal so k=2
Hope you understand
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