for what value of k, -3 is a zero of a polynomial x²-x-(7k+1)
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Answer:
k=11/7
Step-by-step explanation:
Given polynomial is p(x)=x²-x-(7k+1)
If -3 is zero of p(x) then it satisfies the given equation .i.e. p(-3)=0
now, p(-3)=(-3)²-(-3)-(7k+1)=0
=>9+3-7k-1=0
=>11-7k=0
=>7k=11
=>k=11/7
The value of k = 11/7
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