Question

For what value of 'k' 3k+2,6k and 9k-2 from an A.P

Answer 1

If 3k+2 , 6k , 9k-2 are in AP

Then...

6k-(3k+2) = 9k-2-6k

=> 6k-3k-2 = 3k-2

=> 6k = 3k-2+3k+2

=> 6k = 6k

Then..value of k is 1

Answer 2

Step-by-step explanation:

If the value of K is

3k+2,6k,9k-2 are in an Ap....

then,

•- 6k-3k+2=9k-2-6k

•- 6k-3k-2=3k-2

•- 6k=3k-2+3k+2

•- 6k=6k

k = 1

hence,the value of k is 1......