Question

for what value of k , (-4) is a zero of p(X) =x² -x-(2k-2) ?​

Answer 1

here, we are given that -4 has to be the zero of the polynomial p(x)

So we have to find such a value of k so that the given situation is true.

Therefore, we put x=-4 in the polynomial

i. e,

p(-4) = (-4)^2 - (-4) - (2k-2)

= 16+4 -2k +2

=22 -2k

We equate this to 0 ( since, -4 is zero so it should give value of p(-4) =0)

22-2k=0

-2k= -22

so, k= 22/2

i.e, k =11

THATS THE ANSWER!!! I HOPE I HELPED U!

Answer 2

Answer:

Step-by-step explanation:

As we know -4 is zeroes of the given p(x)

So..

(-4)²- (-4) -(2k-2)

=16+4-2k +2=0

20-2k +2 =0

22=2k

Or

2k=22

K=22÷2

K=11

Hope it's helpful for you dear

K