Question

For what value of k,(-4) is a zero of polynomial x^2-x-2k

Answer 1

Answer:

it's given (-4) as a zero.

in the place of x put (-4).

1. $( - 4) {}^{2} - ( - 4) + 2k$
2. $16 + 4 + 2k$
3. $20 = - 2k$
4. k
5. $k = 20 \div ( - 2)$
6. $k = ( - 10)$

Answer 2

Answer:

10

Step-by-step explanation:

Let's substitute x=-4 in the polynomial and equate the polynomial to 0. We get:

(

${( - 4)}^{2} - ( - 4) - 2 \times k = 0 \\ 16 + 4 - 2 \times k = 0 \\ 20 - 2 \times k = 0 \\ 20 = 2 \times k \\ 10 = k$

The value of K= 10 for -4 to be a zero of the polynomial