Question

for what value of k -4 is a zero of polynomial X
$x ^{2} - x - (2k + 2)$

Answer 1

Hey mate!!

First of all,
HAPPY RAKSHA BANDHAN!

Here's your answer!!

Given that:
x = (-4) ..... (1)
p (x) = x^2 - x -2k - 2 ..... (2)

Putting (1) in (2), we get;
${ (- 4)}^{2} - ( - 4) - 2k - 2 = 0 \\ = > 16 + 4 - 2k = 2 \\ = > 20 - 2 = 2k \\ = > 18 = 2k \\ \\ = > \frac{18}{2} = k \\ \\ = > 9 = k$


Hope it helps!!!