Question

for what value of k, -4 is a zero of px = x square -x-(2k-2)

Answer 1

x = -4

p(x) = x² - x - (2k-2)

p(-4) = (-4)² - (-4) - (2k - 2)

=> 16 + 4 - 2k + 2

=> 22 - 2k

=> -2k = -22

=> k = -22/-2

=> k = 11