For what value of k,(-4)is a zero of t e polynomial x-(2k+2)
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Answer:
Step-by-step explanation:
given that
x-(2k+2)=0 and x=-4
putting the value of x in the equation we get
-4-(2k+2)=0
-4-2k-2=0
-6-2k=0
-2k=6
-k=6/2
-k=3
k=-3
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