Question

for what value of k (-4) is a zero of the polynomial x^2 -x- 2k+2)

Answer 1

$\huge \mathtt{ \fbox{Solution :)}}$

Given ,

• The polynomial is (x)² - x - 2k + 2
• The roots of the polynomial is -4

Thus ,

(-4)² - (-4) - 2k + 2 = 0

16 + 4 - 2k + 2 = 0

20 - 2k = -2

-2k = -2 - 20

-2k = -22

k = 22/2

Hence , the value of k is 11

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Answer 2

AnsWer :

k= 11.

Solution :

We have equation,

$\tt {x}^{2} - x - 2k + 2.$

And,

(-4) is zero of this equation, so

$\tt p(x) = 0 \\ \tt p( - 4) = 0.$

Putting,

$\tt p( - 4) = { - 4}^{2} + 4 - 2k + 2. \\ \tt \implies 0= 16 + 4 - 2k + 2. \\ \tt \implies22 = 2k. \\ \tt\implies k = \frac{ \cancel{22}}{ \cancel2} \\ \tt \implies k = 11.$

Therefore,the value of k is 11.