Question

For what value of K, -4 is a zero of the polynomial x^2-x-(2K+2)

Answer 1

Hey friend!! here is your answer

_____________________________

◆Given equation- x^2-x-(2k+2)

◆Put x = -4 in given equation

◆(-4)^2-(-4)-(2k+2)=0

◆16+4-2k-2=0

◆20-2k-2=0

◆18-2k=0

◆-2k=-18

◆k=-18/-2

◆k=9

K=9, so (-4) is a zero of given polynomial

__________________________

⭐️Hope it helps you⭐️

Answer 2

Hey!

_______________

x = -4

p (x) = x^2-x-(2K+2)

p (-4) = (-4)^2 - (-4) - [(2k) + 2] = 0

16 + 4 - 2k - 2 = 0

20 -2 - 2k = 0

18 - 2k = 0

-2k = -18

k = -18/-2

k = 9

_______________

Hope it helps...!!!