Question

for what value of 'k' , -4 is a zero of the polynomial x^2-x-(2k+2)?​

Answer 1

If (-4) is a zero of the polynomial i.e.

$f(x) = {x}^{2} - x - (2k + 2)$

Then, f(-4) should be equal to 0; hence the reqd. equation for the problem

$= > f( - 4) = { - 4}^{2} - ( - 4) - (2k + 2) = 0 \\ = > 16 + 4 - 2k - 2 = 0 \\ = > 18 - 2k = 0 \\ = > - 2k = - 18 \\ = > k = \frac{ - 18}{ - 2} = 9$

HOPE THIS COULD HELP!!!