Question

for what value of k,-4 is a zero of the polynomial x-x(2k+2)

Answer 1

Hi Friend !!!

Here is ur answer !!!

x²-x-(2k+2) =0

Put x = -4

(-4)²-(-4)-(2k+2) = 0

16+4-2k-2 = 0

16-2k+2 = 0

-2k = -18

k = -18/-2

k = 9

Hope it helps u : )

Answer 2

Heya !!!

It seems your question contains some mistake. Polynomial should be X² - X (2K +2)

It is given that -4 is a one zero of the given polynomial.

P(X) = X² - X-(2K+2)

P(-4) = (-4)² - (-4) -( 2K +2)

=> (16) + 4 -( 2K +2)

=> 16 + 4 - 2K -2= 0

=> -2K+18 = 0

=> -2K = -18

=> K = -18/-2

=> K = 9.

HOPE IT WILL HELP YOU.... :-)