Question

for what value of k, - 4 is a zero of the polynomial x²-x-(2k+2)

Answer 1

Given -4 is a zero of the given polynomial. Then we have put , x= -4 then ; (-4)^2-(-4)+(2k+2)=0
16+4+2k+2=0
2k=-22
K=-11

Answer 2

Heya,

Here is the solution:-

-4 is the zero of the polynomial.

So x = -4

x² -x-(2k+2)

(-4)² - (-4) -( 2k+2) = 0

16 +4 -2k-2 = 0

18-2k = 0

-2k = -18

k= 9.

Hope it helps u.............