Question

For what value of k, (-4) is a zero of the polynomial x2-x-(2k+2)?

Answer 1

Hello friend!

Zero of the polynomial is -4

p(x)=x²-x-(2k+2)

p(x)=x²-x-2k-2

p(-4)=0

0=-4²-(-4)-2k-2

0=16+4-2k-2

0=18-2k

2k=18

k=18/2=9

Answer 2

Hi there !!

p(x) = x² - x - [ 2k + 2 ]
     
p(-4) =  [-4]² - [-4] - [ 2k + 2 ]
         = 16 + 4 - 2k - 2  = 0
         = 20 - 2k - 2 = 0
         18 - 2k = 0
18 = 2k
k = 18/2
k = 9