Question

For what value of k, – 4 is a zero of the polynomial x2 – x – (2k + 2)?

Answer 1

Answer:

Given,

A polynomial x2 – x – (2k + 2)

– 4 is a zero of the given polynomial.

As – 4 is the zero,so at x = -4, the value of the polynomial x2 – x – (2k + 2) will be 0.

So we get,

⇒x2 – x – (2k + 2) = 0

⇒( – 4)2 – ( – 4) – (2k + 2) = 0

⇒16 + 4 – (2k + 2) = 0

⇒20 – (2k + 2) = 0

⇒– (2k + 2) = – 20

⇒2k + 2 = 20

⇒ 2k = 20 - 2

⇒2k = 18

⇒k = 18/2

= 9

Answer 2

@brainly..

Putting the another value of zero of polynomial i.e.–4

f(x)=x^2–x–(2k+2)

f(–4)=16–(–4)–(2k+2)

0=20–2k–2

18=2k

9=k