Question

For what value of k, (-4) is a zero of the polynomial x2-x -(2k +2)

Answer 1

Given equation

$x^{2} -x-(2k+2) = 0$

-4 is the zero pf the polynomial

Substituting, we get,

$\implies (-4)^{2} - (-4) - (2k+2) = 0$

$\implies 16 + 4 -2k-2 = 0$

$\implies 20-2-2k=0$

$\implies 18 - 2k = 0$

$\implies -2k = -18$

$\implies k = \dfrac{-18}{-2}$

$\implies \underline{\underline{k = 9}}}}$

$\boxed{\boxed{\bold{Therefore, \ the \ value \ of \ k \ is \ 9}}}}}$

                                                 

Answer 2

Answer:

5

Step-by-step explanation:

value of k is 5

If (-4) is a zero of the polynomial x2-x -(2k +2)