Question

For what value of k,(-4) is a zero of the polynomial x²-x-(2k+2)?

Answer 1

Answer:

-4 is zero value for p(x)=

p(-4)=0

substitute -4 in in polynomial

(-4)^2-(-4)-(2k+2)=0

16+4–2k-2=0

20–2k-2=0

18–2k=0

-2k=-18

k=9

Answer 2

Answer:

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Step-by-step explanation:

So, we will first put it in the equation and solve it.

Let p(x) = x² - x - (2k + 2 )

p(-4) = (-4)² - (-4) - (2k + 2)

[As we need that value that will make it p(-4) the ZERO of the polynomial we will presume it as the zero of the polynomial]

⇒ 0 = 16 + 4 + 2k - 2

⇒ 0  = 18 + 2k

⇒ -18 = 2k  →  k = -18 / 2    →     K = -9