Question

For what value of k, (–4) is a zero of the polynomial x2 – x – (2k + 2)?

Answer 1

x² – x – (2k + 2)

(-4)²+4-2k-2=0

16+2-2k=0

18-2k=0

2k=18

k=9

Answer 2

heya mate here is the answer

p(x) = x² - x - (2k + 2)

p(-4) = (-4)² -(-4)-(2k+2)

=> 16+4-2k-2 = 0

=> -2k = 2 - 20

=> k = -18/-2 = 9

$so \: the \: value \: of \: k \: is \: 9$

if k will 9 then the polinomial x² - x -(2k+2) will have -4 as a factor

hope it helps you