For what value of k, (–4) is a zero of the polynomial x2 – x – (2k + 2)?
Answers
Answered by
5
Heya !!!
P( X ) = X² - X - ( 2K + 2 )
P ( - 4 ) = (-4)² - (-4) - 2K - 2
=> 16 + 4 - 2K - 2 = 0
=> -2K +18 = 0
=> -2K = -18
=> K = 18/2 = 9
★ HOPE IT WILL HELP YOU ★
P( X ) = X² - X - ( 2K + 2 )
P ( - 4 ) = (-4)² - (-4) - 2K - 2
=> 16 + 4 - 2K - 2 = 0
=> -2K +18 = 0
=> -2K = -18
=> K = 18/2 = 9
★ HOPE IT WILL HELP YOU ★
Chinki45:
u got 9 and he got 5
please help
???
u r wrong or he is wrong
Answered by
2
Gn: f(x)=x²-x-(2k+2)
(-4) is a zero.
=>x+4=0
x=-4.
=>f(x)=0.
=>(-4)²-(-4)-(2k+2)=0
=>16+4-(2k+2)=0
=>20=(2k+2)=(k+1)2
=>k+1=10
.: k=9.
(-4) is a zero.
=>x+4=0
x=-4.
=>f(x)=0.
=>(-4)²-(-4)-(2k+2)=0
=>16+4-(2k+2)=0
=>20=(2k+2)=(k+1)2
=>k+1=10
.: k=9.
he got 9 and u got 5
help
,???
Srry I was wrong.Answer is 9.
the correct answer is 5
in book it is given
please check your question properly.
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