Question

for what value of k,( - 4) is a zero of x square + X -( 2 k + 2)

Answer 1

-4 is one zero of the given polynomial X² + X - ( 2K + 2 ).




P ( X ) = X² + X - 2K - 2



Substitute x = -4 in p ( x ).



P (-4) = (-4)² + (-4) - 2K - 2




=> 16 - 4 - 2K - 2 = 0




=> -2K + 16 - 6 = 0



=> -2K + 10 = 0



=> -2K = -10



=> K = 10/2



=> K = 5

Answer 2

$\bold{Hey!!!}$

( - 4 ) is a zero of given polynomial x^2 + x - ( 2k + 2 )

p ( x ) = x^2 +x - 2k - 2

p ( - 4 ) = ( - 4 )^2 + ( - 4 ) - 2k - 2

=> 0 = 16 - 4 - 2k - 2

=> 0 = 10 - 2k

=> 2 k = 10

=> k = 5

$\boxed{k = 5}$

$\textbf{Hope it helps!!!!}$