for what value of k, -4 is a zero of x²-x-(2k+2)?
Answers
Answered by
2
Answer:
k = 9
Step-by-step explanation:
x2 - x- {2k+ 2} = 0
as -4 is the zero of polynomial
(-4)^2 - (-4) - (2k+ 2)= 0
16 + 4 - 2k -2 = 0
18 - 2k = 0
-2k = -18
therefore k = 9
Answered by
0
Step-by-step explanation:
its yur solution .....
Attachments:
Similar questions