Question

For what value of k(-4) is azero of the polynomial x2-x-(2k+2)?.​

Answer 1

Answer:

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Answer 2

Answer:

k=9

Step-by-step explanation:

for -4 to be zero after putting -4 in place of x the solution must be 0

p(-4)=(-4)^2-(-4)-(2k+2)=0

      16+4-2k-2=0

      20-2-2k=0

       18-2k=0

         2k=18

           k=9