Question

for what value of k - 4 is the zero of the polynomial x^2-x-2(k+2).​

Answer 1

Answer:

value of k equals 2 or 9

Step-by-step explanation:

the explanation is given above

Answer 2

Answer:

In the given polynomial f(x)=x

2

−x−(2k+2), substitute x=−4 as shown below:

f(−4)=(−4)

2

−(−4)−(2k+2)=16+4−2k−2=18−2k

Therefore, f(−4)=18−2k.

Since it is given that x=−4 is a zero of the polynomial f(x)=x

2

−x−(2k+2), therefore f(−4)=0 that is:

18−2k=0

⇒2k=18

⇒k= 18

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2

⇒k=9

Hence k=9.