Question

for what value of k ,-4 is the zero of the polynomial x^2-x-(2k+2)

Answer 1

Given:

1) x²-x-(2k+2)=0....... Given Quadratic Equation

2) -4 is the zero of a polynomial I. e x=-4

To Find:

Value of k=?

Solution:

Since,

x=-4...... (Given)

Substituting the value of x in the polynomial,

we get,

x²-x-(2k+2)=0

x²-x-2k-2=0

(-4) ²-4-2k-2=0

16-4-2k-2=0

12-2k-2=0

10-2k=0

10=2k

k=10/2

k=5

So, The value of k is 5 .

Answer 2

Answer:

x= -4 (given)

x^2-x-(2k+2)=0

x^2-x-2k-2=0

(-4)^2-4-2k-2=0

16-4-2k-2=0

12-2k-2=0

10-2k=0

10=2k

k=10/2

k=5.

Explanation:

Hope this answer will help you dear...