for what value of k -4 is the Zero of the polynomial x square minus 2 x minus 2k + 2
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Answered by
3
Given polynomial,
x²-2x-2k+2
-4 is the zero of the polynomial.
p(-4)=(-4)²-2(-4)-2k+2=0
-2k+8+2+16=0
-2k+26=0
-2k=-26
k= -26/-2
k=13
Therefore,the value of k is 13
Hope it helps
x²-2x-2k+2
-4 is the zero of the polynomial.
p(-4)=(-4)²-2(-4)-2k+2=0
-2k+8+2+16=0
-2k+26=0
-2k=-26
k= -26/-2
k=13
Therefore,the value of k is 13
Hope it helps
Answered by
1
A/q if
p(x) = x² -2x - 2k +2
p(-4) = 0
⇒ (-4)² - 2(-4) -2k +2 = 0
⇒ 16 + 8 - 2k + 2 = 26 - 2k = 0 ⇒ k = 13
if your p(x) = x² - 2x - (2k + 2 ) ⇒ x² - 2x - 2k - 2
p(-4) = (-4)² - 2(-4) -2k - 2 = 16 + 8 - 2k - 2 ⇒ 22 - 2k = 0 ⇒ k= 11
so ans is either 13 or 11 as per question ............doubt... ask?
p(x) = x² -2x - 2k +2
p(-4) = 0
⇒ (-4)² - 2(-4) -2k +2 = 0
⇒ 16 + 8 - 2k + 2 = 26 - 2k = 0 ⇒ k = 13
if your p(x) = x² - 2x - (2k + 2 ) ⇒ x² - 2x - 2k - 2
p(-4) = (-4)² - 2(-4) -2k - 2 = 16 + 8 - 2k - 2 ⇒ 22 - 2k = 0 ⇒ k= 11
so ans is either 13 or 11 as per question ............doubt... ask?
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