For what value of k,(-4) is the zeroes of polynomials x2-x-(2k+2)?
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Heyà !!
x² – x – (2k+2) = 0
=> (–4)² – (–4) – (2k+2) = 0
=> 16 + 4 = 2k + 2
=> 20 = 2k + 2
=> 2k = 20 – 2
=> 2k = 18
=> k = 9
x² – x – (2k+2) = 0
=> (–4)² – (–4) – (2k+2) = 0
=> 16 + 4 = 2k + 2
=> 20 = 2k + 2
=> 2k = 20 – 2
=> 2k = 18
=> k = 9
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