Question

for what value of k,-4 is zero of the polynomial
$x {}^{2} - x - (2k + 2)$
​

Answer 1

Answer:

5

Step-by-step explanation:

let p(x) =

$x {}^{2} - x - (2k + 2)$

for zero

x=-4

(4)^2 - 4 - (2k+2)=0

16-4-2k-2=0

10-2k=0

10=2k

k=10÷2

k=5