CBSE BOARD X, asked by samiksha302005, 11 months ago

for what value of k ,- 4 is zero of x^2 -x-(2 k + 2)​

Answers

Answered by aami21
3

substitute-4 instead of x

16+4-(2k+2)=0

20-2k-2=0

18=2k

k=9

Answered by Imanu01
5

❣❣ANSWER❣❣

One zero is -4 then,

X^2-X-(2K+2)

(-4)^2+4-(2K+2)

16+4-2K-2

20-2K-2

18=2K

K=18/2=9

Value of K is 9

HOPE IT HELPS YOU✨✨✌✌

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