for what value of k 4 - K X square + 2 + 4 x + 8 K + 1 is equal to zero is a perfect square
RaunakRaj:
can u write the equation clearly I cant understand the 2nd term and use symbols like , = ^ to make it clear
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b2-4ac=0(given)
(2k+4)2-4(4-k)(8k+1)=0
4k2+16k+16-4(32k+4-8k2-k)=0
4k2+16k+16-128k-16+32k2+4k=0
36k2-108k=0 (Dividing the equation by 4)
9k2-27k=0
9k2=27k
9k=27k/k
9k=27
K=27/9
K=3
hope it will will help you.........
(2k+4)2-4(4-k)(8k+1)=0
4k2+16k+16-4(32k+4-8k2-k)=0
4k2+16k+16-128k-16+32k2+4k=0
36k2-108k=0 (Dividing the equation by 4)
9k2-27k=0
9k2=27k
9k=27k/k
9k=27
K=27/9
K=3
hope it will will help you.........
please mark it as BRAINLIEST
their is no option here bro for it
okay
ok
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