For what value of K 4x-y=11,Kx+3y=5 unique solution no solution
Answers
Answered by
12
condition for the system of linear equations to have no solutions :
a₁/a₂ =b₁/b₂≠ c₁/c₂
given equations ,
K 4x-y=11,
Kx+3y=5
here, a₁ = 4, a₂ = k, b₁= -1 , b₂= 3
4/k = -1/3
12 = -k
k = -12
a₁/a₂ =b₁/b₂≠ c₁/c₂
given equations ,
K 4x-y=11,
Kx+3y=5
here, a₁ = 4, a₂ = k, b₁= -1 , b₂= 3
4/k = -1/3
12 = -k
k = -12
Answered by
7
Answer:
PLZ MARK IT AS BRAINLIEST ANSWER
HOPE THIS WILL HELP YOU ...
Attachments:
Similar questions