Question

For what value of K , 5 is the zero of the polynomial x^2 - 11x + 3k +12 ?

Answer 1

Answer:

k = 6...

Step-by-step explanation:

Answer 2

Ans:

6

Step-by-step explanation:

Given:

p(x)=x² - 11x + 3k + 12

Zero p(x) = 5

To find:

value(k)

Solution:

Because the zero of the polynomial is given, we can substitute the zero of the main variable of the polynomial.

Therefore, p(5)=(5)²- 11(5) + 3k +12 = 0

25 - 55 + 3k + 12 = 0

Solving all the possible operations on the LHS

-18 + 3k = 0

On transposing -18 to RHS

3k = 18

On transposing 3 to RHS

k = 18/3

k = 6

******END OF EXPLANATION******

Hope my explanation was sensible.