Question

For what value of K+9, 2K-1, and 2K+7 are consecutive terms of an A.P

Answer 1

Hi
Nice question

Solution:-

If K + 9, 2K - 1 and 2K + 7 are the consecutive terms of an A.P., then the common difference (d) between these terms will be same.

So,
K + 9 - (2K - 1) = 2K - 1 - (2K + 7)

K + 9 - 2K + 1 = 2K - 1 - 2K - 7

-K + 10 = -8

-K = -8 -10

-K = -18

K = 18

Hope this helps you.

Answer 2

K+9,2K-1,2K+7 are consecutive terms of an A.P

So,common difference (d)=(2K-1)-(K+9)=(2K+7)-(2K-1)

=>2K-1-K-9=2K+7-2K+1

=>K-10=8

=>K=18

The A.P is 27,35,43