Question

for what value of k are 2k+1,6k-1,5k+7are the first three terms of an AP?​

Answer 1

Answer:

As they are terms of AP. The consecutive terms must have common difference.

6k-1-(2k+1)=5k+7-(6k-1)

⇒4k-2=-1k+8

⇒5k=2+8

⇒5k=10

⇒k=10/5

⇒k=2.

Hence, the value of k is 2.