Question

for what value of k are 2k,k+10 and 3k+2 in AP plzz answer quickly

Answer 1

➡HERE IS YOUR ANSWER⬇

Since 2k, k+10 and 3k+2 are in AP,

(k+10) - 2k = (3k+2) - (k+10)

or, - k + 10 = 2k - 8

or, 3k = 18

So, k = 6.

FORMULA USED :

If a, b and c are in AP, then

b - a = c - b.

⬆HOPE THIS HELPS YOU⬅

Answer 2

According to AP,
b - a = c - b
So, 2b = (a +c) __(where a, b and c are terms at respective positions) __

2(k+10) = (2k +3k +2)
or, 2k +20 = 5k + 2
or, 3k =18
or k =6
.
Now k =6 is ur required answer..
Proud to help you.