For what value of k are the no. X,2x+k,3x+6 three consecutive terms of an ap
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In AP t2-t1 = t3-t2
- let t1=x
- t2=2x+k
- t3=3x+6
(2x+k) - (x) =(3x+6) - (2x+k)
2x^2 - kx = 3x+6-2x+k
2x^2- kx = x+6+k..
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