For what value of k are the number x , 2 X + K, 3 X + 6 three consecutive terms of an ap
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for a set of ap, the common difference should be equal,
2x+k-x=3x+6-(2x+k)
x+k=3x+6-2x-k
x+k=x+6-k
2k=6
k=3
2x+k-x=3x+6-(2x+k)
x+k=3x+6-2x-k
x+k=x+6-k
2k=6
k=3
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