Question

for what value of k are the numbers x, 2x + k, and 3x+6 three consecutive numbers of an AP

Answer 1

Step-by-step explanation:

it's given x,2x+kand 3x+6 is consecutive terms of an ap and asking us to find k=?

t1=x,t2=2x+k,t3=3x+6

t2-t1=t3-t2

2x+k-x=3x+6-(2x+k)

x+k=3x+6-2x-k

x+k=x+6-k

k+k=x-x+6

2k=6

k=6/2

k=3

therefore the value of k =3