Question

for what value of k,are the root of quadratic equation (k-4)x^2 + (k+4)x+4=0

Answer 1

↗️Here's your answer↖️

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⇒ ᣝ=b²-4ac=0

⇒(k+1)²-4(k+4)×1=0

⇒K²+2k+1-4k-16=0

⇒k²-2k+1=16

⇒(k-1)²=4²

⇒k-1=+4

: K=1+4

:k=1+4,1-4 or k=5 ,-3

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Hope it helps you dear