for what value of k are the roots of quadratic equation 3 X² + 2 kx + 27=0 equals and real
Answers
Answered by
1
Answer:
k. =9
Step-by-step explanation:
d=0
d. = b² -4ac
d. = ( 2k)² - 4* 3. * 27.
0. = 4k² - 324.
4k² = 324.
k² = 81.
k. = 9.
hope. it. help
Answered by
0
Step-by-step explanation:
The given equation is 3x^2 + 2kx + 27 = 0
Since, the roots are equal and real.
Therefore, Discriminant = 0
=> b^2 - 4ac = 0
=> (2k)^2 - 4×3×27 = 0
=> 4k^2 - 324 =0
=> 4k^2 = 324
=> k^2 = 324/4
=> k^2 = 81
=> k = +9, -9
Thus, value of k is +9 or -9
Similar questions