Question

For what value of k are the roots of quadratic equation 3x2

+2kx +27 = 0 real and equal?​

Answer 1

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ANSWER

⇒ The given equation 3x

2

+2kx+27=0

Here, a=3,b=2k,c=27

It is given that roots are real and equal.

∴ b

2

−4ac=0

⇒ (2k)

2

−4(3)(27)=0

⇒ 4k

2

−324=0

⇒ 4k

2

=324

⇒ k

2

=81

∴ k=±9