Question

For what value of k, are the roots of the quadratic equation 3x² + 2kx + 27 = 0 real and
equal.​

Answer 1

Answer:

k= ±9.

Step-by-step explanation:

condition for real & equal roots ::--

b² - 4ac=0.

(2k)² - 4*3*27=0.

4k² = 324

k²=324/4

k²= 81.

k= ±√81.

k= ±9.

I HOPE IT HELPS U.

HAVE A NICE DAY.

Answer 2

$\huge\tt\purple{«Answer»}$

The given equation 3x²+2kx+27=0

Here, a=3,b=2k,c=27

It is given that roots are real and equal.

∴ b² −4ac=0

⇒ (2k)² −4(3)(27)=0

⇒ 4k² −324=0

⇒ 4k²=324

⇒ k² =81

∴ k= ±9

HOPE IT HELPS

MARK BRAINLIEST PLS