Question

For what value of k are the roots of the quadratic equation kx^2 + 4x + 1 =0 equals and reals ​

Answer 1

Answer:

2x plus 1 = 189

Step-by-step explanation:

Answer 2

the given quadratic equation is kx^2 + 4x + 1 =0 and roots are the reals equal

The find the value of k.

Here, a= k b=4 and c=1

as the konw that D=b^2-4ac

putting the value of a =k b=4 and c=1

D=(4)^2 - 4 ( k) (1)

=16-4k

the given equation will have real and equal roots,

D=0

thus,

16- 4k =0

4k =16

k=16/4

k=4

therefore the value of k=4