for what value of k are the roots of the quadratic equation 3x^2+2kx+27=0 real and equal
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Discriminant= 0
So b^2-4ac =0
4k^2 -4×3×27 =0
4k^2 -324= 0
4k^2 = 324
k^2 = 81
So the value of k is 9.
So b^2-4ac =0
4k^2 -4×3×27 =0
4k^2 -324= 0
4k^2 = 324
k^2 = 81
So the value of k is 9.
dhairyajain79:
thanks
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