for what value of k do dependent linear equations x+2y=4 and 3x+ky=12 represent coincident line
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Answer:
Step-by-step explanation:
the value of k is 6 so that they are coincide lines
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Given; x+2y=4 and 3x+ky=12
To Find; for what value of k do dependent linear equations x+2y=4 and 3x+ky=12 represent coincident line
Solution;
x+2y=4 and 3x+ky=12
a1=1,b1=4 and a2=3, b2=k
for coincident lines
a1/a2=b1/b2=c1/c2
1/4=3/k
k=3/4
Hence the value of k is 3/4
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