For what value of K do the equation 2k-8=6. 1) 6. 2) 7 3)8
Answers
answer
For k = 2, the two equations 3x-y+8=0 and 6x-ky=-16 represent coincident lines.
solutions
The given equations are 3x-y+8=0 and 6x-ky+16 = 0. We have to find the point at which both the equations represent coincident lines.
For the lines to be coincident,
\frac{a_{1}}{a_{2}}=\frac{b_{1}}{b_{2}}=\frac{c_{1}}{c_{2}}
a
2
a
1
=
b
2
b
1
=
c
2
c
1
\text { Here } a_{1}=3, a_{2}=6, b_{1}=-1, b_{2}=-k, c_{1}=8 \text { and } c_{2}=16 Here a
1
=3,a
2
=6,b
1
=−1,b
2
=−k,c
1
=8 and c
2
=16
Substituting the values, we get
\frac{3}{6}=\frac{-1}{-k}=\frac{8}{-16}
6
3
=
−k
−1
=
−16
8
Either \frac{3}{6}=\frac{-1}{-k}
6
3
=
−k
−1
or \frac{-1}{-k}=\frac{8}{16}
−k
−1
=
16
8
k = 2 or k = 2
Therefore for k = 2, both the equations represent coincident lines.
Answer:
2)7
Step-by-step explanation:
2k-8=6
2k=14 (Changing signs when transporting is imp)
k=7